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1.5x^2-3=3
We move all terms to the left:
1.5x^2-3-(3)=0
We add all the numbers together, and all the variables
1.5x^2-6=0
a = 1.5; b = 0; c = -6;
Δ = b2-4ac
Δ = 02-4·1.5·(-6)
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{36}=6$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-6}{2*1.5}=\frac{-6}{3} =-2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+6}{2*1.5}=\frac{6}{3} =2 $
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